(3x-4)(2x^2-5x-7)=0

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Solution for (3x-4)(2x^2-5x-7)=0 equation:


Simplifying
(3x + -4)(2x2 + -5x + -7) = 0

Reorder the terms:
(-4 + 3x)(2x2 + -5x + -7) = 0

Reorder the terms:
(-4 + 3x)(-7 + -5x + 2x2) = 0

Multiply (-4 + 3x) * (-7 + -5x + 2x2)
(-4(-7 + -5x + 2x2) + 3x * (-7 + -5x + 2x2)) = 0
((-7 * -4 + -5x * -4 + 2x2 * -4) + 3x * (-7 + -5x + 2x2)) = 0
((28 + 20x + -8x2) + 3x * (-7 + -5x + 2x2)) = 0
(28 + 20x + -8x2 + (-7 * 3x + -5x * 3x + 2x2 * 3x)) = 0
(28 + 20x + -8x2 + (-21x + -15x2 + 6x3)) = 0

Reorder the terms:
(28 + 20x + -21x + -8x2 + -15x2 + 6x3) = 0

Combine like terms: 20x + -21x = -1x
(28 + -1x + -8x2 + -15x2 + 6x3) = 0

Combine like terms: -8x2 + -15x2 = -23x2
(28 + -1x + -23x2 + 6x3) = 0

Solving
28 + -1x + -23x2 + 6x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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